((8x+3)(9)-(9x-8)(8))/(4x+3)^2

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Solution for ((8x+3)(9)-(9x-8)(8))/(4x+3)^2 equation: 


D( x )

(4*x+3)^2 = 0

(4*x+3)^2 = 0

(4*x+3)^2 = 0

4*x+3 = 0 // - 3

4*x = -3 // : 4

x = -3/4

x in (-oo:-3/4) U (-3/4:+oo)

(9*(8*x+3)-(8*(9*x-8)))/((4*x+3)^2) = 0

(9*(8*x+3)-8*(9*x-8))/((4*x+3)^2) = 0

9*(8*x+3)-8*(9*x-8) = 0

9*(8*x+3)-8*(9*x-8) = 0

91 = 0

91 = 0

91/((4*x+3)^2) = 0

x belongs to the empty set

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